Find the value of ‘z’, if the following equation has equal roots: (z - 2)x2 - (5 + z)x + 16 = 0
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The Brainliest Answer! For any quadratic equation to have equal zeroes, discriminant must equal to 0. discrminant, for ax^2 + bx + c = 0, is given by b^2 - 4ac. Hence the satisfying value of z is 89/64
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