find the value of z : (z/6) -( 2z/3) = 7
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z/6-2z/3 = 7
z-4z/6 = 7
-3z/6 = 7
-3z = 7x6
-3z = 42
z= 42/-3
z= -14
Answered by
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Step-by-step explanation:
we have to solve the question ,z
/2+z/3-z/6 =8
Taking. LCM of denominatora of (z/2), (z/3) and (z/6)
or ,LCM of( 2,3,6)=6
now now write each fraction in such a way that determinator to it will be 6
I.e..,z/ 2 =( 3xz) /( 3x2) =3z/6
z/3=(2xz)/(2x3)=2x/6
z/6=(1xz)/(1x6) =z/6
now , z/2+z/3-z/6 is converted into (3z/6+/6+2z/6-z/6=8
so, 3z/6+2z/6-z/6=8
or , (3z+2z-z)/6 =8
or,(5z-5)/6=8
or , 4z/6=8
or z=12
hence , value of z =12
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