Question

Find
the value of zero (x - 1)(x-2)(x-3) (x-4) ​

Answer 1

Hii...

Here's your answer...

Let the f(x) = (x-1)(x-2)(x-3)(x-4) be the given polynomial.

Here the contant term of f(x) is 24 and the factors of 24 are ±1 ±2 ±3 ±4 ±6 ±12 ±24.

Now,

f(1) = (1-1)(1-2)(1-3)(1-4)

= 0

hence, f(1) is a root of polynomial f(x).

likewise, f(2), f(3) and f(4) are other possible zero of root f(x).

Hope it'll help you...

Thanks...