Math, asked by nonu8498, 6 months ago

Find the value of5/9x2+3x-4 when X=3/5

Answers

Answered by Anonymous
11

Answer:

Given, 2x−(3x−4)=3x−5

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,3x+x=4+5

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,3x+x=4+5⇒4x=9

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,3x+x=4+5⇒4x=9On dividing 4 on both the sides, we get

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,3x+x=4+5⇒4x=9On dividing 4 on both the sides, we getx=

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,3x+x=4+5⇒4x=9On dividing 4 on both the sides, we getx= 4

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,3x+x=4+5⇒4x=9On dividing 4 on both the sides, we getx= 49

Given, 2x−(3x−4)=3x−5⇒2x−3x+4=3x−5⇒−x+4=3x−5Transpose x terms on one side,3x+x=4+5⇒4x=9On dividing 4 on both the sides, we getx= 49

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