Find the value ofK.if the points A(8,1),B(3,-4)andC(2,K)are collinear
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Since the given points (8,1) , (3,-4) , (2 ,k) are collinear,
area of the triangle formed =0 i. e,
1/2 [8 (-4-k)+3 (k-1)+2 (1--4)]=0
1/2 [-32-8k+3k-3+10]=0
1/2 [-5k-25]=0
-5k-25=0×2/1
-5k-25=0
-5k=25
k=25÷-5
=-5
I hope -5 is the answer
area of the triangle formed =0 i. e,
1/2 [8 (-4-k)+3 (k-1)+2 (1--4)]=0
1/2 [-32-8k+3k-3+10]=0
1/2 [-5k-25]=0
-5k-25=0×2/1
-5k-25=0
-5k=25
k=25÷-5
=-5
I hope -5 is the answer
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