Question

Find the value ofp for which the points (-5, 1).(1. p) and (4, -2) are collinear.​

Answer 1

$\huge\boxed{Answer...}$

◆↪️"The given points are collinear then area formed by them is 0."↩️◆

Area = 0

x1(y2 - y3) + x2( y3 - y1)+ x3(y1- y2)=0

(-5)[p-(-2)] + 1(-2-1) + 4{1-p} = 0

-5(p+2) + 1(-3) + 4(1-p) = 0

-5p - 10 -3 + 4 - 4p =0

-9p -13 +4 = 0

-9p -9 = 0

-9(p +1 ) = 0

p + 1 =0

p = -1

$\huge{The.. Value..Of ..p ..Is.-1}$

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