find the value ofx^3+1/x^3
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0
Answer:
x^3 x 1 / x^3
x^3/x^3 = 1
remaining 1 x 1 = 2
Answered by
0
Answer:
let ,x³=y
y+1/y
y²+1/y
let's compare with 0
y²+1=0
y=±√-1/2
y=-iota/2 (or) iota/2
so ,
x³=y
x=³√-iota/2 or³√iota/2
pls mark brainliest
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