Question

Find the value ofx, if the distance between the points (x, -1) and (3,2) is 5units.​

Answer 1

Answer:

$x = - 7 \\ x = 1$

Step-by-step explanation:

Given

$\sqrt{( {x - 3)}^{2} + { (- 1 - 2)}^{2} } = 5$

$\sqrt{ {(x - 3)}^{2} + 9 } = 5$

Squaring both sides

${(x - 3)}^{2} = 25 - 9 = 16$

$x - 3 = ±4$

Hence

$x = - 7 \\ x = \: \: 1$