Question

Find the value oh k for Quadratic equation (2x)2-x+k=0,so that they have two equal roots

Answer 1

Answer: -2

Step-by-step explanation:

Given equation

2x(2-x)+k=0

4x-2x$x^{2}$+k=0

-2x$x^{2}$+4x+k=0

2x$x^{2}$-4x-k=0

a=2, b=-4, c=-k

It has equal roots.

Δ=0

b²-4ac=0

(-4)²-4(2)(-k)=0

16+8k=0

8k=-16

k=-2