Question

⚡Find the value ok 'k'⚡


(1) kx² + 2x – 3 = 0, x = 2
(iii) x2 + 2ax - k = 0, x = -a


✨Correct Answer please✨​

Answer 1

Answer:

(1)

$k {x}^{2} + 2x - 3 = 0 \\ k {2}^{2} + 2 \times 2 - 3 = 0 \\ 4k + 4 - 3 = 0 \\ 4k + 1 = 0 \\ 4k = - 1 \\ k = \frac{ - 1}{4}$

Step-by-step explanation:

(ii)

${x}^{2} + 2ax - k = 0 \\ { (- a)}^{2} + 2a \times a - k = 0 \\ {a }^{2} + 2{a}^{2} - k = 0 \\ 3 {a}^{2} - k = 0 \\ k = 3 {a}^{2}$