Question

Find the value ok so that the poin 2,3, k,6 and 3,2 are collinear

Answer 1

Answer:

k= -1

Step-by-step explanation:

for points to be collinear

it should satisfy:

$\frac{1}{2}[ x_1 (y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)] = 0$

x_1=2

x_2=k

x_3=3

y_1=3

y_2=6

y_3=2

substituting and simplifying we get...

$\frac{8-k-9}{2} =0$

k=-1.

hope it helps..