Question

Find the value ork for which the roots are real and equal of equation
( 3k + 1 ) xsq + 2 ( k + 1 ) x + k = 0​

Answer 1

Answer:

Answer

Open in answr app

Open_in_app

Given equation is y=(3k+1)x

2

+2(k+1)x+1=0

Also, it is given that the equation has equal roots.

Then D=0⇒b

2

−4ac=0

a=3k+1 b=2(k+1) c=1

b

2

−4ac=[2(k+1)]

2

−4(3k+1)=0

⇒4k

2

+4+8k−12k−4=0

⇒4k

2

−4k=0

⇒4k(k−1)=0

⇒k=0 k=1

When k=0

equation y=x

2

+2x+1=0

Roots are x=−1,−1

When k=1

equation 4x

2

+4x+1=0

Roots are x=

2

−1

,

2

−1

verified_toppr