find the value os i¹⁸ , í¹⁰⁸ , i⁹⁶ , i⁷⁶.
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Answered by
1
Answer:
all are positive 1 because all iota value are in even that's why 1)(i^2)^16 2) (i^2)^106 3) (i^2)^94 4) (i^2)^74
Answered by
0
Answer:
i¹⁸=(i²)⁹
=-1⁹
=-1
i¹⁰⁸=(i⁴)²⁷
=1²⁷
=1
i⁹⁶=(i⁴)²⁴
=1²⁴
=1
i⁷⁶=(i²)³⁸
=-1³⁸
=-1
Step-by-step explanation:i⁴=1,
i²=-1
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