Question

find the value os n in each of the following

Answer 1

9.

iii)
${5}^{2n - 1} \div 25 = {5}^{3} \\ \\ {5}^{2n - 1} \div {5}^{2} = {5}^{3 } \\ \\ {5}^{2n - 1} = {5}^{3} \times {5}^{2} \\ \\ {5}^{2n - 1} = {5}^{5} \\ \\ thus \\ \\ 2n - 1 = 5 \\ \\ 2n = 5 + 1 \\ \\ 2n = 6 \\ \\ n = 6 \div 2 \\ \\ \\ n = 3$