Question

find the value ...please ​

Answer 1

Answer:

option c) x = 62°

               y = 30°

Step-by-step explanation:

As PQR is a isosceles triangle with PR = QR ;

therefore ∠RPQ = ∠RQP = 59°

on angle sum property of triangle PQR we get;

∠QPR + ∠PQR + ∠PRQ

59 + 59 + x .= 180°

x = 62°  

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∠PRQ + ∠PRS = 180°      ---—--—--—--—-—--—---—-—-—-— (straight line)

as PRQ = x = 62°;

PRS = 180 - 62

PRS = 118°

on angle sum property of triangle PRS we get;

∠RPS + ∠PRS + ∠PSR = 180°

32 + 118 + x = 180°

y = 180 - 150

y = 30°

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