find the value
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Answer:
(3x)^2x = 9
Step-by-step explanation:
1) 3^x * 3^3 = 1/(3^4)^x - 2
2) 3^x * 3^3 = 1 / 3^4x * 3^-8
3) 3^x * 3^3 * 3^4x = 1/1/3^8
4) 3^5x + 3 = 1 * 3^8
(since bases are same we can equate the powers
5x + 3 = 8
5x = 5
x = 1
(3x)^2x = (3 * 1)^2 * 1 = 3^2 = 9
Answered by
27
5x + 3 = 8
5x = 8 - 3
5x = 5
x = 1
3× 1 ^2 × 1 = 3² = 9
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