Question

Find the value.. Pls answer it urgently..

Answer 1

sin(90-61)/cosec61+ 2{cot(90-82).cot(90-73).cot45.cot73. cot82}-3{sin square(90-52)+cos square52}


cosec61/cosec61+2{tan82.tan73.1.cot73.cot82}-3{cos square 52+cos square 52}

since cot45=1 we will substitute it's value and sin square theta + cos square theta =1 ,we will substitute it's value also and cosec 61 /cosec61 =1 and tan theta=sin theta /cos theta and cot theta =cos theta /sin theta

1+2{sin82/cos82.sin73/cos73.1.cos73/sin73.cos82/sin82}-3{1}

1+2{1}-3{1}
1+2-3
3+-3
0