find the value
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1/5 Mark me as brainlieast and follow me
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pari8349:
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10^(2y) = 25
Since the base is 10, we can write,
log (25) = 2y
=> log (5^2) = 2y
=> 2 log (5) = 2y
=> log (5) = y
=> - log (5) = - y
=> log (5^(-1)) = - y
=> log (1/5) = - y
From this, we get that,
10^(- y) = 1/5
Hence 1/5 is the answer.
Here I used only one identity.
log(x^a) = a · log (x)
And conversely,
a · log (x) = log (x^a)
Or, we can find the answer without using logarithm!
10^(2y) = 25
=> (10^y)^2 = 5^2
=> 10^y = 5
Now, since 10^(2y) = 25 is given, divide LHS by 10^(2y) and RHS by 25. So,
(10^y) ÷ (10^(2y)) = 5 ÷ 25
=> 10^(y - 2y) = 1/5
=> 10^(- y) = 1/5
So we got the answer. We can find out the answer by this too.
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