Math, asked by kulwinderkaur2868, 8 months ago

find the
value roots of quadratic
equation
of
the
x²- x-6 are​

Answers

Answered by sivayogeshs47
1

Answer:

Step-by-step explanation:

Write as  

x

2

x

6

=

0

Notice that  

3

×

2

=

6

And that  

3

2

=

1

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

We need the product (multiplication answer) to be negative (-6)

So either 3 is negative and 2 positive or the other way round as  

(

a

)

×

(

+

b

)

=

a

b

But the  

x

as the coefficient of -1

So if  

(

a

)

+

(

+

b

)

=

1

then  

a

must have the biggest value

So we have to have  

(

3

)

+

(

+

2

)

=

1

and  

(

3

)

×

(

+

2

)

=

6

all as required.

x

2

x

6

 

=

 

(

x

3

)

(

x

+

2

)

Answered by dhritidas
2

Step-by-step explanation:

 {x}^{2}  - x - 6 = 0 \\ =  >   {x}^{2}  - 3x + 2x - 6 = 0 \\  =  > x(x - 3) + 2(x - 3) = 0 \\  =  > (x + 2)(x - 3) = 0 \\  =  > x + 2 = 0 \:  \:  \:  \:  \: or \:  \:  \:  \:  \:  x - 3 = 0 \\  =  > x =  - 2 \:  \:  \:  \:  \: or \:  \:  \:  \:  \:  x = 3 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: the \: solutions \: are \:  - 2 \: and \: 3 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x =  - 2 \: and \: 3

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