Question

Find the value(s) of k for which (k – 4)x2 + 2(k - 4)x + 4 = 0 has real and equal roots.​

Answer 1

Answer:

2k-4k+2k-4k+4=0

2k=-4

k=2

Answer 2

Answer:

12/4x

Step-by-step explanation:

(k-4)*2+2(k-4)x+4=0

2k-8+2(k-4)x+4=0

2k-8+2k-8*x+4=0

4k-16*x=-4

4k*x=-4+16

4k*x= 12

4k=12/x

k=12/4x