Find the value(s) of k for which the pair of linear equations kx + y = k2 and x + ky = 1 have infinitely many solutions.
Answers
Answered by
392
According to question
Equations given
kx + y = k^2
and
x + ky = 1
Since the equations have infinitely many solutions
Thus
comparing the coefficients of x and y
k/1 = 1/k = 2k/1
thus
k = +1 or -1
k = +1/ root2 or -1/ root2
Equations given
kx + y = k^2
and
x + ky = 1
Since the equations have infinitely many solutions
Thus
comparing the coefficients of x and y
k/1 = 1/k = 2k/1
thus
k = +1 or -1
k = +1/ root2 or -1/ root2
Answered by
252
Answer: 1
Step-by-step explanation:
For pair of equations kx + 1y = k2 and 1x + ky = 1
We have :
For infinitely many solutions,
k^2 = 1
k = -1 , 1
k^3 = 1
⇒ k = 1
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