find the value(s) of k for which the pair of linear equations kx+y=k^2and x+ky=1 have infinitely many solutions
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Condition for infinitely many solutions,
a1/a2=b1/b2=c1/c2
a1=k b1=1 c1=k^2
a2=1 b2=k c2=1
k/1=1/k
k^2=1^2
k= under root 1
Therefore, k=1
a1/a2=b1/b2=c1/c2
a1=k b1=1 c1=k^2
a2=1 b2=k c2=1
k/1=1/k
k^2=1^2
k= under root 1
Therefore, k=1
gayatripadhee7p2sllr:
thanks you soo much
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