Question

Find the value(s) of k for which the points A(0,2k) B(-2,6) C(3,1) is 10 sq. units.
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Answer 1

Answer:

Step-by-step ll explanation:

Area of triangle = [ x1( y2-y3) + x2( y3-y1) + x3(y1- y2)] ÷2

Here,

x1 = 0, x2 = -2, x3 = 3

y1 = 2k, y2 = 6, y3 = 1

[0(6-1) + (-2)(1-2k) + 3(2k-6)] ÷2 =10

0 - 2 + 4k +6k - 18 = 10

10k - 20 = 10

10k = 30

K = 3