Question

find the value (s) of k for which the quadratic equation x²+2√kx+8=0 has equal roots.​

Answer 1

Answer:

they have equal roots .

so b^2-4ac=0

compare the above equation with ax^2+bx+c=0

a=1. b=2√k. c=8

so

(2√k)^2 -4×1×8=0

4k^2=32

k^2=8

k=. +-2√2