Find the value(s) of k for which the quadratic equation x2 + 2/2 kx +18 = 0 has equal roots.
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Step-by-step explanation:
when the quadratic equation has real roots then its discriminants will be equal to zero.
so by the above condition b²-4ac=0
so,(2/2k)²-4×1×18=0
4/4k²-72=0
4/4k²=72
4k²=4/72
4k²=1/18
k²=1/36
k=1/6
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