Question

Find the value(s) of k for which the quadratic equation x² + 2v2kx + 18 = 0 has equal
roots​​

Answer 1

Answer:

put

Step-by-step explanation:

determenent of this equation to zero and solve

for k

Answer 2

Answer:

Step-by-step explanation:

The given equation is

x²+2v²kx+18=0

The roots are equal when the discriminant=0

=>(2v²k)²-4×18×1=0

=>4v⁴k²-4×18=0

=>v⁴k²-18=0

v⁴k²=18

=> k²=18/v⁴

=>k=√18/v⁴

=> k=3√2/v².(answer)

Hope you got it.