Find the value(s) of k for which the quadratic equation x² + 2v2kx + 18 = 0 has equal
roots
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Answered by
0
Answer:
put
Step-by-step explanation:
determenent of this equation to zero and solve
for k
Answered by
0
Answer:
Step-by-step explanation:
The given equation is
x²+2v²kx+18=0
The roots are equal when the discriminant=0
=>(2v²k)²-4×18×1=0
=>4v⁴k²-4×18=0
=>v⁴k²-18=0
v⁴k²=18
=> k²=18/v⁴
=>k=√18/v⁴
=> k=3√2/v².(answer)
Hope you got it.
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