Math, asked by deepak456verma, 1 month ago

Find the value(s) of k, for which the roots of the equation 3x

2 + 2k− 11k = 0

are real and equal.​

Answers

Answered by SHIVAMDHASMANA
11

Answer:

3x² −5x + 2k= 0

⇒ Here, a=3,b=−5,c=2k

⇒ It is given that roots are real and

equal

∴ b² −4ac = 0

⇒ (−5)² − 4(3) (2k) = 0

⇒ 25−24k=0

⇒ 24k = 25

∴ k = 24/25

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