Find the value(s) of k, for which the roots of the equation 3x
2 + 2k− 11k = 0
are real and equal.
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Answer:
3x² −5x + 2k= 0
⇒ Here, a=3,b=−5,c=2k
⇒ It is given that roots are real and
equal
∴ b² −4ac = 0
⇒ (−5)² − 4(3) (2k) = 0
⇒ 25−24k=0
⇒ 24k = 25
∴ k = 24/25
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