Find the value (s) of k, if the quadratic equation 3x square - k root 3x+4=0 has equal roots
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Answered by
0
given the quadratic equation has equal roots
so,
b^2-4ac=0
=(-k root 3)^2-4×3×4=0
=3k^2-48=0
=k^2=48/3
=k^2=16
=k=4
so,
b^2-4ac=0
=(-k root 3)^2-4×3×4=0
=3k^2-48=0
=k^2=48/3
=k^2=16
=k=4
Answered by
0
Hi ,
compare 3x² - k √3 x + 4 = 0 with
ax² + bx + c = 0 ,
a = 3 , b = - √3 k , c = 4 ,
according to the problem given ,
roots are equal .
discreaminant = 0
b² - 4ac = 0
( √3 k )² - 4 × 3 × 4 = 0
3k² = 48
k² = 48/3
k² = 16
k = ±√16
k = ± 4
I hope this helps you.
:)
compare 3x² - k √3 x + 4 = 0 with
ax² + bx + c = 0 ,
a = 3 , b = - √3 k , c = 4 ,
according to the problem given ,
roots are equal .
discreaminant = 0
b² - 4ac = 0
( √3 k )² - 4 × 3 × 4 = 0
3k² = 48
k² = 48/3
k² = 16
k = ±√16
k = ± 4
I hope this helps you.
:)
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