Find the value(s) of k, if the quadratic equation 3x²-k√3x+4=0 has equal root
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0=b²+4ac in equal roots
a=3,b=-k√3,c=4
(-k√3)²+4*4*3=0
3k²+48=0
-48=3k²
-48÷3=k²
-16=k²
4=k
a=3,b=-k√3,c=4
(-k√3)²+4*4*3=0
3k²+48=0
-48=3k²
-48÷3=k²
-16=k²
4=k
deepikachaudhary190:
thanks , your answer help me a lot
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Hope it helps you ...
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