Question

Find the value(s) of k in: x squared + (k+6)(x) - 2k = 0 such that:
i) 3 is a root of the quadratic.
ii) the roots are equal in magnitude but opposite in sign
iii) the roots are reciprocals of one another.
iv) the roots are real

Answer 1

1) (k-2)x^2 - 5x +2k + 3 =0 , the roots are reciprocals of eachother. Find the value of k.

(the answer should be k= -5)

2) Find values of n in the equation 2x^2-5(n-1)x + 12=0 if the two roots are consecutive.

(the answer should be n= -1, 3)