Find the value
Sec20 sec40 sec80=?
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Answered by
35
1/(cos20°.cos40°.cos80°)
first find value of (cos20°.cos40°.cos80°)
let A = 20°
we know,
cosA .cos(60°-A).cos (60°+A) = 1/4cos3A
so,
cos20°.cos40°.cos80° =1/4cos3(20°)
= 1/4cos60°= 1/8
hence,
sec20° .sec40°.sec80° = 8
first find value of (cos20°.cos40°.cos80°)
let A = 20°
we know,
cosA .cos(60°-A).cos (60°+A) = 1/4cos3A
so,
cos20°.cos40°.cos80° =1/4cos3(20°)
= 1/4cos60°= 1/8
hence,
sec20° .sec40°.sec80° = 8
maria9:
g8 answer abhi :)
Answered by
29
hope it helps
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