Math, asked by Adrija2609, 1 year ago

Find the value
Sec20 sec40 sec80=?
Work out the problem plz
Thank u

Answers

Answered by abhi178
35
1/(cos20°.cos40°.cos80°)

first find value of (cos20°.cos40°.cos80°)
let A = 20°

we know,

cosA .cos(60°-A).cos (60°+A) = 1/4cos3A
so,
cos20°.cos40°.cos80° =1/4cos3(20°)

= 1/4cos60°= 1/8

hence,
sec20° .sec40°.sec80° = 8

maria9: g8 answer abhi :)
abhi178: thanks
Answered by harshitha8
29
hope it helps

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