find the value sin130°/sin50°
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Answered by
17
We know that sin(180-x) = sin x
So, sin 130 = sin 50
So, sin130/ sin 50= 1
So, sin 130 = sin 50
So, sin130/ sin 50= 1
victory1venkatesh:
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Answered by
29
sin 130
=sin ( 90 + 40 )
= cos (40)
sin 50
= sin ( 90-40)
= cos 40.
substitute sin130 and sin50 in sin130/sin/50
==> sin130/sin50
= cos40/cos40
= 1.
=sin ( 90 + 40 )
= cos (40)
sin 50
= sin ( 90-40)
= cos 40.
substitute sin130 and sin50 in sin130/sin/50
==> sin130/sin50
= cos40/cos40
= 1.
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