Math, asked by Anonymous, 1 year ago

find the value sin18/cos72+root3(tan10*tan30*tan40*tan50*tan80)

Please fast......


suraj5321: ans 1

Answers

Answered by Anonymous
1
sin18/cos( 90-18) + √3 ( tan 10 tan 30 tan( 90-50) tan50 tan ( 90-10)

sin 18/ sin 18 + √3 ( tan 10 × 1/√3 × cot 50 × tan 50 × cot 10)

1 + 1

2

Anonymous: 10
suraj5321: 10
Answered by aakashvishwakarma58
1
hope its help for you dear........☆☆☆






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