Math, asked by BharatLuthra7344, 1 year ago

Find the value, tan1°.tan2°.tan3°................tan90

Answers

Answered by abhigyanprakash2002
3

tan1.tan2.........tan89

but tan 89 can be written as cot 1[tan(90-1)=cot 1] by tan(90-theta)=cot(theta)

likewise......,

tan 88 =cot 2

tan 87= cot 3

................up to tan 46=cot 44

then middle one is tan 45 =1

so it is

tan1.tan2...........tan44.tan 45.cot44..............cot1

tan and cot cancel out by[tan (theta)*cot(theta)=1

so ....remaining is 1

answer =1

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