Question

find the value
$( \frac{2}{3} {}^{ - 2} )$
Simplify
$( \frac{1}{3} ) {}^{ - 2} - ( \frac{1}{2} {}^{ - 3} ) \div ( \frac{1}{4} ) {}^{ - 2}$
No spamm
No copy
​

Answer 1

Answer-1

$( \frac{2}{3}) {}^{ - 2} = \frac{2 {}^{ - 2} }{3 {}^{ - 2} } = \frac{3 {}^{2} }{2 {}^{2} } = \frac{9}{4}$

Answer-2

$( \frac{1}{3} ) {}^{ - 2} - ( \frac{1}{2 } ) {}^{ - 3} \div ( \frac{1}{4} ) {}^{ - 2} \\ = ( \frac{1 {}^{ - 2} }{3 {}^{ - 2} } - \frac{1 {}^{ - 3} }{2 {}^{ - 3} } ) \div \frac{1 {}^{ - 2} }{4 {}^{ - 2} } \\ = ( \frac{3 {}^{2} }{1 {}^{2} } - \frac{2 {}^{3} }{1 {}^{3} } ) \div \frac{4 {}^{2} }{1 {}^{2} } \\ = (9 - 8) \div 16 = \frac{1}{16} \\ answer = \frac{1}{16}$

Answer 2

$\boxed{Explained\:Answer}$

______________________________