find the value
![\sqrt[3]{343} \\ \sqrt[3]{720} \sqrt[3]{343} \\ \sqrt[3]{720}](https://tex.z-dn.net/?f=++%5Csqrt%5B3%5D%7B343%7D+++%5C%5C++%5Csqrt%5B3%5D%7B720%7D+)
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Answer:
∛343 = 7³
∛720 IS NOT A PERFECT CUBE
BUT
729 IS THE NEAREST CUBE NUMBER
WHICH IS,
∛729 = 9
I HOPE YOU UNDERSTOOD THE QUESTION!!!
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