Math, asked by shikha721658, 1 month ago

Find the value
value of: (1\2)^1 + (1\6)^-1​

Answers

Answered by beyzadem1
1

HELLO

1/2+6/1

1/2+12/2

13/2=6, 5

İ hope it helps.

GOOD LUCK

Answered by LaCheems
8

QUESTION:- value of: (1\2)^1 + (1\6)^-1

ANSWER:-

 {( \frac{1}{2}) }^{1}  +  {( \frac{1}{6} )}^{ - 1}  \\  \\  \frac{1}{2}  +  \frac{6}{1}  \\  \\  =  \frac{1 + 12}{2}  \\  \\  =  \frac{13}{2}

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