Question

Find the value vof the given expressions when a= 0, b=-1,c=1 i) A2 - B2 ii) A2 + 2ab +B2 iii)3ab+3ac+c2 iv) 5a/10-4b ​

Answer 1

Solutions :-

1) a^2 - b^2

[By using identity a^2 - b^2

= ( a + b ) ( a - b) ]

( a + b) ( a - b)

Here, The value of a = 0 , b = -1 and c = 1

Therefore,

( 0 + (-1)) ( 0 - ( -1 ))

( 0 - 1 ) ( 0 + 1 )

-1 * 1 = -1

2) a^2 + 2ab + b^2

Here, The value of a = 0 , b = -1 and c = 1

Put the required values in the given expression,

0^2 + 2* 0 * -1 + ( -1 )^2

0 + 0 + 1

= 1

3) 3ab + 3ac + c^2

Here, The value of a = 0 , b = -1 and c = 1

Put the required values,

3*0*(-1 ) + 3*0*1 + 1^2

0 + 0 + 1

= 1

4) 5a/10 - 4b

5a/10 - 4b = 0

Transposing 10 - 4b on RHS

5a = 0 * ( 10 - 4b)

5a = 0

Here, The value of a = 0

Therefore,

= 5 * 0

= 0$.$

Answer 2

Answer:

$\huge \purple{ \underline { \underline \mathfrak \red{Solution}}}$

1) a^2 - b^2

[By using identity a^2 - b^2

= ( a + b ) ( a - b) ]

( a + b) ( a - b)

Here, The value of a = 0 , b = -1 and c = 1

Therefore,

( 0 + (-1)) ( 0 - ( -1 ))

( 0 - 1 ) ( 0 + 1 )

-1 * 1

= -1

2) a^2 + 2ab + b^2

Here, The value of a = 0 , b = -1 and c = 1

Put the required values in the given expression,

0^2 + 2* 0 * -1 + ( -1 )^2

0 + 0 + 1

= 1

3) 3ab + 3ac + c^2

Here, The value of a = 0 , b = -1 and c = 1

Put the required values,

3*0*(-1 ) + 3*0*1 + 1^2

0 + 0 + 1

= 1

4) 5a/10 - 4b

5a/10 - 4b = 0

Transposing 10 - 4b on RHS

5a = 0 * ( 10 - 4b)

5a = 0

Here, The value of a = 0

Therefore,

= 5 * 0

= 0