Question

Find the value with explain plzz:-

Answer 1

$\huge{\underline{\underline{Question\::-}}}$

Find value of $(3^0 + 4^{-1} ) \times 2^2$

$\huge{\underline{\underline{Answer \::-}}}$

♦ Steps involved

1) Arranging Numbers in order

2) Using the rules of BODMAS

3) Simplification of results

$\underline{\underline{solution\::-}}$

♦ Solving bracket first

$(3^0 + 4^{-1} ) \times 2^2$

= $(3^0 + \dfrac{1}{4}) \times 2^2$


♦Now we will take the value of $3^0$ which is equal to 1

= $(1+ \dfrac{4}) \times {2^2}$

= $\dfrac{4 + 1 }{4} \times 4$


= $\dfrac{5 }{4} \times 4$

♦ Dividing the number


= 0.125 × 4


♦ Multiplication at last


= 0.125 × 4

= 5

Answer 2

$\underline{\textbf{\huge{Question}}}$

$\mathbf{({3}^{0} + {4}^{ - 1} ) \times {2}^{2} }$

$\underline{\textbf{\huge{Answer}}}$

According to Law of Exponent.

$\mathbf{{x}^{0} = 1}$

Above Can be Written as.

$\mathbf{(1 + {4}^{ - 1} ) \times {2}^{2} }$

According to Law of Exponent

$\mathbf{( {x})^{ - a} = \frac{1}{x} ^{a}}$

Above Can Written as

$\mathbf{(1 + \frac{1}{4} ) \times {2}^{2}}$

According To BODMAS

Bracket Work will done 1st.

$\mathbf{( \frac{4 + 1}{4} ) \times {2}^{2} } \\ \\ \implies\mathbf{( \frac{5}{4} ) \times {2}^{2} } \\ \\ \implies\mathbf{( \frac{5}{4} ) \times 4} \\ \\ \implies\mathbf{ \frac{\cancel{20}}{\cancel4} } \\ \\ \mathbf{\implies5}$

$\boxed{\mathbf{\huge{Answer=5}}}$