find the value with full solution
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make it a perfect square as
(sin²a+cos²a)²
which when you write the 2ab term while expending a square fn there you have to multiply and divide by 2
thus your answer is 1
(sin²a+cos²a)²
which when you write the 2ab term while expending a square fn there you have to multiply and divide by 2
thus your answer is 1
hunnyfalgun221p2e8il:
tell the full solution
not coming
this is the full solution
when im multiplying and dividing it by 2 it doesn't work
you will get 2sin²acos²a now multiply by 2 you have 4 sin²acos²a which is sin²2a and dividing by 2 you will get 1/2sin²2a
i hope now you have got my piont
thanks a lot :-)
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