Question

Find the value x
-5 ( x+ 12 ) + 17 ( 2- x) ÷ 8 = 1 - 7x​

Answer 1

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To solve :

$\tt ~~~~~~~~~~- 5(x + 12) + 17(2 - x) \div 8 = 1 - 7x$

$\tt \implies (- 5x + - 60) + (34 - 17x) \div 8 = 1 - 7x$

$\tt \implies ( - 5x - 60) + \frac{(34 - 17x)}{8} = 1 - 7x$

$\tt \implies (- 5x - 60) + (34 - 17x) = 8(1 - 7x)$

$\tt \implies ( - 5x - 60) + (34 - 17x) = 8 - 56x$

$\tt \implies (- 5x - 17x) + (34 - 60) = 8 - 56x$

$\tt \implies - 22x - 26 = 8 - 56x$

$\tt \implies - 22x + 56x = 8 + 26$

$\tt \implies 34x = 34$

$\tt \implies x = \frac{34}{34}$

$\tt \implies x = \underline{\underline{1}}$

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Answer 2

Answer:

−5(x+12)+17(2−x)÷8=1−7x

\tt \implies (- 5x + - 60) + (34 - 17x) \div 8 = 1 - 7x⟹(−5x+−60)+(34−17x)÷8=1−7x

\tt \implies ( - 5x - 60) + \frac{(34 - 17x)}{8} = 1 - 7x⟹(−5x−60)+

8

(34−17x)

=1−7x

\tt \implies (- 5x - 60) + (34 - 17x) = 8(1 - 7x)⟹(−5x−60)+(34−17x)=8(1−7x)

\tt \implies ( - 5x - 60) + (34 - 17x) = 8 - 56x⟹(−5x−60)+(34−17x)=8−56x

\tt \implies (- 5x - 17x) + (34 - 60) = 8 - 56x⟹(−5x−17x)+(34−60)=8−56x

- 22x - 26 = 8 - 56x⟹−22x−26=8−56x

- 22x + 56x = 8 + 26⟹−22x+56x=8+26

34x = 34⟹34x=34

x = \frac{34}{34}⟹x=

34

34

$\tt \implies x = \underline{\underline{1}}⟹x= </p><p>1$

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