Question

Find the value x if ( 2x + 1 ), ( 3x + 1 ) , ( x + 16) are in A.P​

Answer 1

Answer:

sorry I can't ...

...

...

...

Answer 2

Assume these expressions are in ascending order and that they are consecutive terms of the arithmetic progression.

What is the common difference d ? Have that

d=3x−(x+1)=3x−x−1

=2x−1

and d=4x+2−3x=x+2 .

Since d=d , set these two differences equal to each other to obtain x :

2x−1=x+2⟹x=3,

and this is the answer to the problem.

The three given terms of the a.p. are then

x+1=3+1=4 ,

3x=3(3)=9 , and

4x+2=4(3)+2=12+2=14.

The common difference is d=5.