Question

Find the value (x+y)^2 + (x-y)^2

Answer 1

Answer:

$2( {x}^{2} + {y}^{2} )$

Step-by-step explanation:

${(x + y)}^{2} = (x + y)(x + y) \\ \\ {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ \\ {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ \\ = > {(x + y)}^{2} + {(x - y)}^{2} = 2( {x}^{2} + {y}^{2} )$

HOPE IT HELPS

Answer 2

Answer:

2(x2+y2) is right answer friend