Question

find the value (x-y)³ + (y-z)³+ (z-x)³ in polynomials
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Answer 1

(x-y)³+(y-z)³+(z-x)³=3(x-y)(y-z)(z-x) as x³ + y³ + z³-3xyz=( x+y+z)(x²+y²+z²-xy-yz-xz) and as (x+y+z)=(x-y+y-z+z-x)=0 so the right part becomes 0 and x³+y³+z³=3xyz. Please mark the answer as brainliest.