find the value x, y, z of a parallelogram whose one angle = 100
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Answer:
let ,x=z(opposite sides of parallelogram ARE equal)
y=100(same)
NOW,
x+y+z+100= 360(as we know property of quadrilateral)
=>x+100+x+100=360(x=a,y=100)
=>2x+200=360
=>2x=160
=>x=80=z
Therefore, x=80,y=100 and z=80(is equal to x)
Step-by-step explanation:
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