Math, asked by aliasgarlightwala75, 1 day ago

find the value X3-6x2+11 at x=0,2,1,3,-1​

Answers

Answered by MagicalGiggles
0

Step-by-step explanation:

If x = 0

  • x³ - 6x² + 11
  • 0³ - 6(0)² + 11
  • 0 - 0 + 11
  • 0 + 11
  • 11

If x = 2

  • x³ - 6x² + 11
  • 2³ - 6(2)² + 11
  • 8 - 6(4) + 11
  • 8 - 24 + 11
  • -5

If x = 1

  • x³ - 6x² + 11
  • 1³ - 6(1)² + 11
  • 1 - 6 + 11
  • 6

If x = 3

  • x³ - 6x² + 11
  • 3³ - 6(3)² + 11
  • 27 - 6(9) + 11
  • 27 - 54 + 11
  • -16

If x = -1

  • x³ - 6x² + 11
  • (-1)³ + 6(-1)² + 11
  • -1 + 6(1) + 11
  • -1 + 6 + 11
  • 16
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