Question

find the value y if
$\frac{x}{2} + \frac{y}{3} = 1$

Answer 1

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find the value y if
$\frac{x}{2} + \frac{y}{3} = 1$


$\sf\frac{3x+2y}{6}=1$
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$\sf\:3x+2y\:=\:6$

2y=6-3x

Answer 2

Hey mate


Here u go

Follow me

X/2 + y/3 = 1
X+y= 1×3×2
X+Y = 6
y = 6-x