Question

find the value
(y²+2y-3) ÷(y-1)
​

Answer 1

Answer:

wait for a while fro the solution.

y²+3y-y-3÷y-1

y(y+3)-1(y+3) /(y-1)

(y-1)(y+3)/(y-1)

y+3 ans.

Answer 2

Answer:

$\frac{ {y}^{2} + 2y - 3 }{y - 1}$

$y - 1) {y}^{2} + 2y - 3(y + 3 \\ \: \: {y}^{2} - y \\ \: \: 3y - 3 \\ \: \: 3y - 3 \\ \: \: 0$

Answer:-

$y + 3$