find the valuem of a cylinder whose hight is 10cm and raise of base is 5cm π=3.14
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Answer:
Volume of remaining solid = volume of cylinder - volume of cone.
r=5 cm (given)
h=12 cm
Volume of cylinder = πr
2
h
=3.14×5
2
×12
=942cm
2
Volume of cone =
3
1
πr
2
h=
3
1
×3.14×5
2
×12
=314cm
3
Remaining volume = 942-314
=628cm
3
Total surface of remaining solid = conical sutface area of cone + Area of circle + Cylindrical area of cylinder.
Conical sutface area of cone =πr
r
2
+h
2
=204.203 cm
2
Conical of cirle = πr
2
=78.54cm
2
Cylindrical area of cylinder = 2πrh
=376.8cm
2
Total surface area 659.543cm
2
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