Question

Find the valueof p, if x, 2x + p and 3x + 6 are in A.P

Answer 1

Answer:

3

Step-by-step explanation:

See, If three terms a,b,c are in A.P,

b-a=c-b which is equal to the common difference.

Hence,

2b = a+c

From the above question, we have,

a= x , b=2x+P , c=3x+6

Therefore,

2(2x+P) = x + 3x + 6

or, 4x+2P=4x+6

or, 2P=6

or, P=3

Done!

Answer 2

Answer:

The value of $p=3$

Step-by-step explanation:

Since $x, 2x+p, 3x+6$  are in an AP, we calculate the value of p using the common difference $d$.

Because, $x,x+d,x+2d$  are the first three terms of an AP.

here,             $d=2x+p-x=x+p$

therefore $2x+p+x+p=3x+6$

that is, $3x+2p=3x+6$

implies      $2p=6$

therefore, $p=3$.

thank you